Skip to main content

Programming (C , C++, VHDL & Java)

Search This Blog

C Programming Tutorial - 17 - if statement with multiple conditions

on May 15, 2018

Get link
Facebook
Twitter
Pinterest
Email
Other Apps

Get link
Facebook
Twitter
Pinterest
Email
Other Apps

Comments

Post a Comment

Popular Posts

XHTML and CSS Tutorial - 5 - Bold, Italics, and Comments

<!doctype html> <html> <head> <title> This is the title Sucker! </title> </head> <body> <h1>Best Website Ever!</h1> <p>This is my paragraph</p> <h2>This is the second header</h2> <p>This is the second paragraph.<br/>And now I'm done with this tutorial</p> </body> </html> <!doctype html> <html> <head> <title> This is the title Sucker! </title> </head> <body> <h1>Best Website Ever!</h1> <p>This is my paragraph</p> <hr /> <h2>This is the second header</h2> <p>This is the second paragraph.<br/>And now I'm done with this tutorial</p> </body> </html> <!doctype html> <html> <head> <title> This is the title Sucker! </title> </head> <body> <h1>Best Website Ever!</h1> <

Java Programming Tutorial - 69 - Drop Down List Program

package apples; import java.awt.*; import java.awt.event.*; import javax.swing.*; public class Gui extends JFrame { private JComboBox box; private JLabel picture; private static String[] filename = {"b.png", "x.png"}; private Icon[] pics = {new ImageIcon (getClass().getResource( filename [0]))}; public Gui() { super ("the title"); setLayout (new FlowLayout()); box = new JComboBox ( filename ) ; box.addItemListener( new ItemListener() { public void itemStateChanged (ItemEvent event) { if(event.getStateChange()== ItemEvent. SELECTED ) picture.setIcon(pics[box.getSelectedIndex()]); } } ); add(box); picture = new JLabel (pics[0]); add(picture); } } package apples; import javax.swing.JFrame; public class apples { public static void main (String[] args) { Gui go = new Gui(); go.setDefaultCloseOperation(JFram

ISBN-13 Assignment - C Programming Source Code

An International Standard Book Number (ISBN) is a unique number assigned to each book. ISBN-13 has thirteen digits in 5 parts which the last digit is “check digit”. The check digit is base ten, and can be 0-9. To compute a missing check digit, each digit, from the left to right, is alternatively multiplied by 1 or 3.Then, the sum of these products should be divided by 10 to find the remainder ranging from 0 to 9. Finally, the check digit can be found by subtracting the remainder from 10, that leaves a result from 1 to 10. For example, take the ISBN 978-0-306-40615-? : a) Firstcalculatesumofproducts:9×1+7×3+8×1+0×3+3×1+0×3+6×1+4×3 + 0×1 + 6×3 + 1×1 + 5×3 = 93 b) Remainder upon dividing by 10 is 3. c) Remainder is subtracted from 10. d) Check digit is 7 (10 - 3).

Powered by Blogger

Theme images by enot-poloskun